12. Multistep Terrance and Jesse are trainingfor a long-distance race. Terrance trains ata rate of 6 miles every half hour, and Jessetrains at a rate of 2 miles every 15 minutes.a. What is the unit rate in miles per hourfor each runner?12 miles8 milesTerrance: Ihr Jesse! Thrb. How long will each person take to runa total of 50 miles at the given rates?Terrance: 4 hr 10 minJesse: 6hr 15 minSandra runs at a rate of 8 miles in45 minutes. How does her unit ratecompare to Terrance's and to Jesse's?I need the most help with C PLZZZZ
Accepted Solution
A:
Answer:a) Terrance's speed- 12 [tex]\frac {{textrm{ miles}}}{{textrm{ hours}}}[/tex] Jesse's speed -8 [tex]\frac{{textrm{ miles}}}{{textrm{ hour}}}[/tex] b) Teerance ;- 4 hr 10 min ; Jesse ;- 6 hr 15 minc) Sandra's speed :- [tex] 10 \dfrac{2}{3} \frac{{textrm{ mile}}}{{textrm{ hour}}}[/tex]Step-by-step explanation:Terrance runs in [tex] \frac {1}{2} [/tex] an hour 6 miles So in 1 hour he / she runs [tex] (6 \times 2) [/tex] miles = 12 miles.So Terrance's speed is 12 [tex] \frac {{textrm{ miles}}}{{textrm{ hours}}}[/tex] ---(1) Jesse's runsIn 15 minutes 2 miles So, In 1 minute [tex] \frac {2}{15} [/tex] milesSo, in 60 minutes [tex] \frac {2}{15} \times 60[/tex] miles = 8 milesSo, Jesse's speed is 8 [tex]\frac{{textrm{ miles}}}{{textrm{ hour}}}[/tex] ----------(2)Terrance runs, 12 miles in 1 hourso, 1 mile in [tex] \frac {1}{12} [/tex] hourso, 50 miles in [tex] \frac {50}{12} [/tex] hour= [tex] 4 \dfrac{1}{6} [/tex] hour=4 hour [tex] \frac {60}{6} [/tex] minutes= 4 hour 10 minutes.Jesse runs,8 miles in 1 hour so, 50 miles in [tex] \frac {50}{8} [/tex] hour= [tex] 6 \dfrac{1}{4} [/tex] hour= 6 hour [tex] \frac {60}{4} [/tex] minutes= 6 hour 15 minutesSandra runs,in 45 minutes 8 milesso, in 1 minute [tex] \frac {8}{45} [/tex] mileso, in 60 minutes [tex] \frac {8}{45} \times 60 [/tex] miles= [tex] 10 \dfrac{2}{3} [/tex] milesSo Sandra's speed is , [tex] 10 \dfrac{2}{3} \frac{{textrm{ mile}}}{{textrm{ hour}}}[/tex]---------------- (3)